Differentiation Value (Math Help)

Introduction to differentiation value:

The process of finding a derivative is called differentiation. The derivative is a measure of how a function changes as its input changes. Loosely speaking, a derivative can be thought of as how much one quantity is changing in response to changes in some other quantity; for example, the derivative of the position of a vehicle with respect to time is the instantaneous velocity at which the vehicle is traveling.

General formula for differentiation:

d / dx (x^n) = nx^n - 1

d / dx (constant) = 0

d / dx (Ay) = A (dy / dx)

d / dx (uv) = u (dv / dx) + v (du / dx)

d / dx (u / v) = (v (du / dx) - u (dv / dx)) / v^2

Example problems - differentiation value

Differentiation value problem 1:

Find the differentiation value of the function f(x) = 3x^5 - 5x^2 + 9x

Sol : Given function f(x) = 3x^5 - 5x^2 + 9x

Differentiate the given function with respect to x, we get

f' (x) = (3 * 5)x^4 - (2 * 5)x + 9

= 15x^4 - 10x + 9

Answer : The final answer is 15x^4 - 10x + 9

Differentiation value problem 2:

Find the differentiation value of the function f(x) = 7x^4 - 12x^3 + 12x - 76 and findf' (4).

Sol : Given function f(x) = 7x^4 - 12x^3 + 12x - 76

Differentiate the given function with respect to x, we get

f' (x) = (7 * 4)x^3 - (12 * 3)x^2 + 12 - 0

= 28x^3 - 36x^2 + 12

Substitute x = 4 in the above equation, we get

= 28 (4)^3 - 36 (4)^2 + 12

= 1228

Answer : The differentiation value is 1228

Differentiation value problem 3:

Find the differentiation value of the function f(x) = 4x^2 - 22x^3 + 56x and findf' (2).

Sol : Given function f(x) = 4x^2 - 22x^3 + 56x

Differentiate the given function with respect to x, we get

f' (x) = (4 * 2)x - (22 * 3)x^2 + 56

= 8x - 66x^2 + 56

Substitute x = 2 in the above equation, we get

= 8 (2) - 66 (2)2 + 56

= 192

Answer: The differentiation value is 192

Practice problems - differentiation value

Differentiation value problem 1:

Find the differentiation value of the function f(x) = 12x^6 - 23x^3 + 7x^2 + 89

Answer : The differentiation value is 72x^5 - 69x^2 + 14x

Differentiation value problem 2:

Find the differentiation value of the function f(x) = x^5 - 7x^4 + 12x^3 + 17x^2

Answer : The differentiation value is x^4 - 28x^3 + 36x^2 + 34x

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Greatest Common Divisor definition (dave hook)

The greatest common divisor of 2 or more without zero integers, is the biggest +ve integer that is divide the all numbers lacking a remainder The another name of the greatest common divisor is the greatest factor(gcf), greatest common denominator, highest common divisor. For example greatest common divisor of 8 and 12 is 4.Now we see about the Greatest common divisor definition.

Greatest common divisor definition Examples:

Greatest common divisor definition Example 1:

Find the greatest common divisor of given numbers 48, 180

Solution:

48 is written by 48 = 2 x 2 x 2 x 2 x 3

180 is written by 180 = 2 ? 2 ? 3 ? 3 ? 5.

Therefore the greatest common divisor = 2 x 2 x 3 = 12

Greatest common divisor definition Example 2:

Find the greatest common divisor of given numbers 21, 15

Solution:

21 is written by 21 = 3 x 7

15 is written by 15 = 3 x 5

Therefore the greatest common divisor = 3

Greatest common divisor definition Example 3:

Find the greatest common divisor of given numbers 15, 21, 18

Solution:

15 is written by 15 = 3 x 5

21 is written by 21 = 3 x 7

18 is written by 18 = 3 x 3 x 2

Therefore the greatest common divisor = 3

Greatest common divisor definition Example 4:

Find the greatest common divisor of given numbers 15, 21

Solution:

15 is written by 15 = 3 x 5

21 is written by 21 = 3 x 7

Therefore the greatest common divisor = 3

Greatest common divisor definition More Examples:

Greatest common divisor definition Example 1:

Find the greatest common divisor of given numbers 25, 65

Solution:

25 is written by 25 = 5 x 5

65 is written by 65 = 5 x 13

Therefore the greatest common divisor = 5

Greatest common divisor definition Example 2:

Find the greatest common divisor of given numbers 8, 64, 128

Solution:

8 is written by 8 = 2 x 2 x 2

64 is written by 64 = 2 x 2 x 2 x 2 x 2 x 2

128 is written by 128 = 2 x 2 x 2 x 2 x 2 x 2 x 2

Therefore the greatest common divisor = 2 x 2 x 2 = 8

Greatest common divisor definition Example 3:

Find the greatest common divisor of given numbers 8, 18

Solution:

8 is written by 8 = 2 x 2 x 2

18 is written by 18 = 2 ? 3 ? 3.

Therefore the greatest common divisor = 2

Preparation for greatest common factor - example problems.

here we are going to prepare some example problems for gcf

Preparation example: 1

Find the greatest common denominator for 18, 16 using prime factorization method.

Solution:

First we have to find the prime factor for each number

Prime factor for 18 = 2, 3, 3

Prime factor for 16 = 2, 2, 2, 2

Here the common terms for both = 2

Therefore the gcf of given number is = 2

Preparation example: 2

Find the greatest common factor for 55,121

Solution:

First we have to find the prime factors for each

Prime factor for 55 = 5, 11

Prime factor for 121 = 11,11

Here the common term = 11

Therefore the gcf of 55, 121 = 11

Preparation for greatest common factor - example: 3

Preparation example: 3

Find the greatest common factor for 48, 124, and 76

Solution:

First we have to find the prime factor for each one

Prime factor for 48 = 2, 2, 2, 2, 3

Prime factor for 124 = 2,2, 31

Prime factor for 76 = 2,2,19

Here the common factor is 2, 2

Therefore the gcf of given number is 2 * 2 = 4

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Some Important Compounds of Calcium (p Nitin)

The important compounds of calcium are

Gypsum and Plaster of paris

Mortar

Gypsum and Plaster of paris :

In nature , calcium sulphate occurs as gypsum and also as anhydrite . Alabaster is finely divided naturally calcium sulphate . The presence of calcium causes permanent hardness to water .

In the laboratory, calcium sulphate is prepared by the action of dil H2SO4 on lime (CaO) or CaCO3 . On concentration of the solution , gypsum CaSO4.2H2O separates out .

CaO + H2SO4 + H2O ---- CaSO4.2H2O

CaCO3 + H2SO4 + H2O ---- CaSO4.2H2O + CO2

Calcium sulphate or gypsum is sparingly soluble in water . Its solubility decreases on heating . It dissolves in solutions like that of ammonium sulphate due to double salt formation . When heated to 120oC to 130oC , a half hydrate or a hemihydrate ( CaSO4. H2O ) is formed . The hemihydrate is often referred to as plaster of paris . Both gypsum and plaster of paris lose water of hydration at 200oC and are converted into anhydrous calcium sulphate , known as "Dead burnt" CaSO4 . This is so called because it does not set with water .

Plaster of paris , when mixed with water ( half of its amount by weight ) becomes a paste which sets to a hard mass on standing . The process is known as "setting" . As the mass becomes hard , its volume increases and finally changes to CaSO4.2H2O .

There are two stages in the setting of plaster of paris . In the first stage , known as "setting stage" , the hemihydrate changes into orthorhombicdihydrite . In the second phase orthorhombic dihydrate is converted into mono-clinic dihydrate , gypsum . This stage is known as "hardening stage" .

Plaster of paris is used in the manufacture of crucibls , models etc . Surgeons use it for setting the fractured bones in position . Dentists also use it in hospitals . Toys are made with it . In the preparation of chalks used in class room teaching , plaster is used .

Gypsum is used in the preparation of cement and plaster of paris .

Mortar is an important compounds of calcium

An intimate mixture of 1 part of slaked lime , 3 parts of sand and water is known as lime "mortar" . Sand makes mortar porous and also harder . While hardening , sand prevents the cracks on contraction . Even though mortar was used in the construction of houses for several decades , it is not clearly known how it becomes so hard . Evaporation of water may be one of the reasons . Slaked lime , when mixed with sand , hardens slowly , due to formation of calcium silicate .

Ca(OH)2 + SiO2 gives CaSiO3 + H2O

Similarly , it may combine with CO2 to form calcium carbonate .

Ca(OH)2 + CO2 gives CaCO3 + H2O

Mortar becomes hard with time due to several chemical reaction taking place at the centre of the mass .

Mortar , mixed with cement is called "cement mortar" . This is stronger than mortar .

Lime stone and clay when heated together give "hydraulic mortar" .This can set like cement on addition of water . This is used for bleaching purposes and as an antiseptic .

Uses of Calcium

It is used as a reducing agent in the extraction of metals like uranium , zirconium and thorium .

It is also used as an alloying agent in the production of beryllium , aluminium , copper , lead and magnesium alloys .

It is also used as an deoxidizers , desulfurizer for various ferrous and non-ferrous alloys .

Understand more on about the Periodic Table Gases, and its Illustrations. Between, if you have issue on these Bromine Molar Mass keep verifying my content i will try to help you. Please discuss your feedback.

Coping with exam stress - The role of parents (Nachita Jaiswal)

It is only natural to feel a little bit of stress before and after your exam results. A little stress is healthy and can motivate you to plan your road ahead. However, it gets complicated when students stress too much before the exam results are out. This is the time of CBSE and State board exam results and one could read several reports in the newspapers on how students are reacting to the pressure.

It is not uncommon to find students panicking and in their fit committing suicide. It is time that parents should wake up to help their kids deal with exam stress. There have been cases in the past where the parents were seen to put too much pressure on their ward, pushing them to take a drastic step.

Remember, high grades are important to scale up on the educational front and explore various streams, but it is not the end of it all. In these competitive times, when there are infinite career options in front of students, they are already burdened with their own thoughts. What stream should I choose? Should I go for medical or engineering? What if I made a wrong choice? What if I fail to score high, would I still get an admission in an institute of repute?
Just try and be in their shoes and you will know exactly how stressed they are. To add to the stress are our constant comparison with the siblings or friends. Are we doing justice when we force our child to get high grades or face the consequence?

How can you help your ward to cope?

1. Inculcate a positive thinking

Help your kid strike a balance in his thoughts and behavior. Instead of focusing on the negative, make him understand the power of positive thinking. The exam is already over and nobody can go back and change anything, just make them understand that thinking positive can help them plan their future better. Worrying is a waste of time and can never reap anything good.

2. Make them join some activity class

So your child just appeared for a CBSE 10th standard exam? He is anxious about his results and cannot concentrate on any activity except worrying. As a supporting parent, divert his attention. You know what your child enjoys the most, make sure you enroll him to his favorite activity class. It could be anything a guitar class, or a general exercise class.

3. Introduce them to meditation

Meditation is a powerful mind and body exercise and hence you should ensure to teach your kids about the benefits of meditation. It is one of the best tools to cope with anxiousness, worry and panic situations.

Hope these tips can help your child to cope with the after result exam stress.

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Function of Cell Membrane (Omkar Nayak)

Introduction to function of cell membrane:

Cell membrane or plasma membrane is one of the most important parts of a cell that encloses and protects the components of a cell. Cell membrane separates the interior of a cell from outside environment. It is like a covering that encloses the different organelles of the cell and the cytoplasm that contains these organelles. In brief cell membrane physically separates the contents of the cell from the outside environment. The major function of cell membrane is the same in plant cell and animal cell. The membrane is made of two layers of phospholipids and each phospholipid molecule has a head and a tail region. The head region is called hydrophilic which shows attraction towards water molecules and the tail ends are known as hydrophobic which repels water molecules. The cell membrane also contains lots of protein molecules, which are embedded in the phospholipid layer. All these constituents of the cell membrane work jointly to carry out the functions of cell mem,brane.The functions of cell membrane are described below.

Functions of membrane:

The following are the major functions of cell membrane

Protection: one of the basic functions of a cell membrane is to act like a protective outer covering for the cell. The following are some of the cell membrane functions.
Support: Cell membrane anchors the cytoskeleton or cellular 'skeleton' made of protein and contained in the cytoplasm and gives shape to the cell.
Cell membrane helps in cell adhesion: Cell membrane is responsible for attaching the cell to the extracellular matrix so that the cells group together to form tissues.

Other functions of cell membrane

Transport of materials: Cell membrane helps in the transportation of materials needed for the functioning of the cell organelles. The semi-permeable cellmembrane of the cells helps in the transferring of those nutrients and chemicals that are required for the cell functioning. Transport may be either active at the expense of cellular energy or passive, without using cellular energy.
The proteins present in the cell membrane receive signals from the outside environment and convert the signals to messages that are passed to the organelles inside the cell.
Receptor for various substances: Proteins present on cell membrane act as a receptors or sites for hormone molecules the signal which cell to start or stop metabolic activity.
Act as barrier: The cell membrane surrounds cell and physically separates the intracellular components from the extracellular environment.
Cell communication: Specific proteins embedded in the cell membrane can act as molecular signals that allow cells to communicate with each other.
Immunity: Protein receptors can function to receive signals from both the environment and other cells. Other proteins on the surface of the cell membrane serve as "markers" that identify a cell to other cells. The interaction of these markers respective receptors forms the basis of cell in the immune system.

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Number Theory Homework Tutoring (Nandan Nayak)

Introduction to number theory homework tutoring:

In this article we will see about number theory homework tutoring. Number theory homework tutoring is nothing but it is also the basic chapters of mathematics. The number theory problems will be simple and easier. Number theory homework tutoring is done by the tutors in online process. Below are some of the solved example problems under this topic of number theory. Number theory homework tutoring will include the problems on the topics like scientific notation, prime factorization etc.

Number theory homework tutoring

Homework tutoring is done by the tutors of tutor vista. There are many tutors of high qualification are always ready to provide tutoring for the students.

Solved problem 1: Write standard form of the given scientific notation 3.432 ? 102

Solution:

Given 3.432 ? 102

To find the standard form just multiply the scientific notation by 10.

10 are raised with the powers of 2. So shift the decimal point two places to the right side. 3.432 --> 343.2

3.432 ? 102 = 343.2

Solved problem 2: Find the least common multiple of 3 and 8

Solution:

Given 3 and 8

To find the least common multiple (LCM), we have to list out the multiples of 3 and 8.

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

Multiples of 8: 8, 16, 24, 32, 40, 48

The least common multiple of 3 and 8 is 24. Since 24 is the least common number that comes first in the multiples of both 3 and 8

Solved problem 3: Find the prime numbers in the given series of numbers 14, 16, 19, 21, 25, 29

Solution

Prime numbers are divisible only by 1 and the number itself. It does not have any other multiples. Here we check the given numbers

Multiples of 14 = 1, 2, 7, 14

Multiples of 16 = 1, 2, 4, 8, 16

Multiples of 19 = 1, 19

Multiples of 21 = 1, 3, 7, 21

Multiples of 25 = 1, 5, 25

Multiples of 29 = 1, 29

So here 19 and 29 are the prime numbers of the given series of numbers.

Number theory homework tutoring

Below are some of the practice problems about number theory homework tutoring.

1. Find the prime numbers of the series given below

35, 37, 39, 41, 45

2. Find the LCM of 7 and 9

3. Write the standard form of the scientific notation given 5.243x 102

4. Find the LCM of 11 and 6

5. Find out the prime numbers of the given 42, 63, 70,71

Answer

1. 37, 41

2. 63

3. 524.3

4. 66

5. 71

A number is a mathematical object used in counting and measuring. A notational symbol which represents a number is called a numeral, but in common usage the word number is used for both the abstract object and the symbol, as well as for the word for the number. In addition to their use in counting and measuring, numerals are often used for labels (telephone numbers), for ordering (serial numbers), and for codes (ISBNs).Let us see about the articles is solving math number problems.

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Neutron Star Black Hole (Nandan Nayak)

The birth, life and death of a star is determined by interplay of nuclear reactions and the gravitational forces. The nuclear reactions that take place in the interior of the star will create a radiation pressure which in turn tries to push the star outward. However the gravitational forces between the particles of the star will try to pull it inward towards the center.When there is a balance between the outward radiation pressure and the inward gravitational pressure the star attains stability. However, when the nuclear fuel inside the core of a massive star gets exhausted, the star collapses under its own enormous gravitational force., As a result the star shrinks to a smallest size. This collapsed star will be so dense that even light cannot escape from it. Such an entity in the cosmos is called 'Black hole'

Introduction to Neutron Star Black Hole

A star is formed when a large amount of interstellar gas, mostly H2 and He starts to collapse on itself due to the gravitational attraction between the gas atoms or molecules . As the gas contracts it heats up due to atomic collisions. As the gas continues to contract, the collision rate increases to such an extent, that the gas becomes very hot, and the gas atoms are stripped off their electrons, and the matter is in a completely ionized state, containing bare nuclei and electrons. Such a state of matter is called plasma state. Under these conditions, the bare nuclei have enough energy to fuse with each other. Thus hydrogen nuclei fuse in such a manner to form helium with the release of large amount of energy in the form of radiation. The radiation emitted in this process is mostly emitted in the form of visible light, UV light, IR light etc., from its outer surface. This radiation is what causes the star to shine, which makes them visible (Ex : Sun and other visible stars).

Neutron star black hole : Process

The star at the stage is halted from gravitational collapse( contraction) since the gravitational attraction of matter towards the centre of the star is balanced by the out ward radiation pressure. A star will remain stable like this for millions of years, until it runs out of nuclear fuel such as H_ and He. The more massive a star is , faster will be the rate at which it will use its fuel because greater energy is required to balance the greater gravitational attraction owing to greater mass i.e., massive stars burn out quickly. When the nuclear fuel is over, i.e., when the star cools off, the radiation pressure is not sufficient to halt the gravitational collapse. The star then begins to shrink with tremendous increase in the density. The star eventually settles into a white dwarf, Neutron star or Black hole depending upon its initial mass

Neutron Star and Black Hole : Conditions

For a star to become a neutron star, its initial mass must be greater than ten solar masses. (M> 10Ms ). As a star with initial mass M > 10 Ms cools off the large mass of the star causes it to contract abruptly, and when it runs out of fuel it springs back and explodes violently. This explosion flings most of the star matter into space and such a state of star is called a Supernova. A supernova explosion is very bright and outshines the light of an entire galaxy. The mass of the matter left behind is greater than 1.4 Ms . If the mass of the left over matter is between 1.4 Ms and 3 Ms Neutron stars evolve. At this stage the repulsion between electrons will not be able to halt further gravitational collapse. Under such conditions, the protons and electrons present in the star combine to form neutrons. After the formation of neutrons, the outward degeneracy pressure between neutrons prevents further gravitational collapse, and the matter left over is called the Neutron Star.

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Probability Survey (p Nitin)

The probability survey is the way of expressing an event that will occur. The probability survey is the event, the experiments that are repeatedly done under some predefined conditions. The results for one or more experiments are not equal. These types of experiments are called as the random experiments or simply experiments. The probability includes the sample space, trail and different forms of events.

Terms present in the probability survey:

Sample space indicates the total number of possibilities for an experiment.
Trial corresponds to the experiment is performed.
Event specifies the outcome of the experiments.
Exhaustive events are an event which contains all the necessary possible outcomes of the experiment.
Mutually exclusive events are the two events that cannot occur simultaneously.
The probability certain likely defines the equally likely event in the probability. Equally likely event means that the two or more events have an equal probability. For example while tossing the die the probability for getting the tail and also the probability for getting the head are the equally likely events. The equally likely event determines the equal probability for the events.

Example problems for probability survey:

Ex 1 :A jar has 6 gray and 9 red marbles. What is the probability to get one gray marbles from the urn without replacement?

Sol:

The number of marbles in the jar is 6 gray and 9 red marbles.

The total numbers of marbles are 15 marbles.

The possibility for getting a gray ball is 6.

The required probability is 6/15 .

Ex 2 : While tossing a fair die, find the complementary probability of the numbers greater than 3.

Sol:

The sample space for the die is S= {1, 2, 3, 4, 5, 6}

The total number of sample space =6.

A is the event for getting the number greater than 3.

A= {4, 5, 6}

The number of events greater than 3 is n (A) =3

P (A) =n (A)/ n(S)

P (A) = 3/6

P (A) = 1/2

The probability for getting the numbers greater than 3 is 1/2 .

The formula for the complementary probability is 1- P (original probability).

The required probability = 1-P (A)

The required probability = 1- 1/2

The required probability = 1/2

The complementary probability for the numbers greater than 3 is 1/2 .

Survey of probability of certain likely events:

Some examples for probability certain likely:

Probability for getting the head and the tail when a coin is tossed only one time.
The probability for getting the number 3 and number 4 are equally likely events.
If an urn contains 5 white balls and 5 red balls. In that the probability for getting the single white ball and also the probability for getting the single red ball are the equally likely events.

Ex 3 : A jar has 5 gray and 7 green marbles. What is the probability to get one gray marbles and also probability for getting 1 green marbles? Determine whether the above events are equally likely events.

Sol:

The number of marbles in the jar is 5 gray and 7 green marbles.

The total numbers of marbles are 12 marbles.

The possibility for getting a gray marble is 5.

The probability for getting one gray marble is 5/12.

The possibility for getting a green marble is 7.

The probability for getting one green marble is 7/12.

The probabilities are 5/12 and also 7/12. These two probabilities are not the equally likely event because the probability of that two events are not same they are different.

Ex 4 : A single six face die is rolled. Find the probability for getting the number 6 and also 3. Determine whether these two events are equally likely events are not.

Sol:

The sample space for the die is S= {1, 2, 3, 4, 5, 6}

The total number of sample space is 6.

The probability for getting the number 3 is 1/6 .

The probability for getting the number 6 is 1/6 .

The probabilities for the two events are 1/6 and 1/6 respectively. The probabilities for the two events are equal. So these two events are equally likely events.

Practice problems:

Two coins are tossed at the same time. What is the probability to get two tails?
Ans: 1/2 .

Learn more on about Division Fractions and its Examples. Between, if you have problem on these topics Subtracting Fraction, keep checking my articles i will try to help you. Please share your comments.

avogadro's law problems with solutions (dave hook)

Relationships between properties of gases can be measured by changing one property while holding the others constant. Avogadro's Law relates the properties of gases to the amount of gas present. Avogadro's law states that the volume of a gas at a given temperature and pressure is directly proportional to the amount of gas, in moles. Thus, V is proportional to n, the number of moles of the gas, AT CONSTANT TEMPERATURE and PRESSURE.

Avogadro said that quantity and volume are directly related:

V 'alpha' n 'rArr' V/n is a constant

Or for the same sample of gas at constant temperature and pressure,

V1/ n1 = V2 / n2

Let us take an example of avogadro's law problems with solutions:

If we have 8 molecules of H2 and 4 molecules of O2, we get 12 molecules and a combined volume. If we then react the mixture, we end up in 8 molecules of gaseous water molecules, which occupy the same volume as the 8 molecules of any other gas.

8 H2 (g) + 4 O2 (g) ? 8 H2O (g)

Avogadro Law Concept Based Questions: avogadro's law problems with solutions

1. Which sample represents the smallest number of moles?
a) 1L H2 at STP
b) 1L Argon at STP
c) 1L of H2 at 27 ? C and 760mm of Hg

Solution:

Let us consider each situation.
At STP, 22.4 L volume will have 1 mole of the gas.
So, in a) 1L of H2, there will be (1L) (1 mole) / 22.4L = 0.0446 moles
˜ 0.045 moles

Similarly in b) 22.4 L of Ar would correspond to 1 mole.

So, 1L would be = (1L) (1 mole) /22.4L = 0.045 moles

In c) we should use the ideal gas equation: PV = nRT
P = 760 mm of Hg V = 1 L T = 27 ? C = (27 +273) K
= 1 atm = 300 K

Therefore, n = PV/ RT
R is the gas constant that has a value of 0.0821 atm L mol -1 K-1
n = [(1 atm) (1 L)] / [(0.0821 atm L mol -1 K-1) (300 K)]

= 0.0406 moles
So the correct option is c) 1L H2 at 27 ? C and 760 mm of Hg.

2. Which of the samples would have the same number of particles?

a) 1L He at STP and 1L O2 at STP
b) 2L He at STP and 1L of He at STP
c) 1L He at 27 ? C and 760 mm of Hg; and 2L He at STP

Solution:

a) In 22.4 L of gas, there will be 1 mole of the gas

So, in 1L of He there will be (1L) (1 mole) /22.4L = 0.0446 moles
˜ 0.045 moles

In 1L of O2, the number of moles will be the same, 0.045 moles.

Now, we know that in every mole, there will be Avogadro number of particles = 6.023 x 10 ^23 particles.

So in 0.045 moles, there will be
(0.045 moles) x (6.023 x 10 ^23 particles)/ 1 mole
= 2.7 x 10 22 number of particles

So, this is the required answer: a) 1L He at STP and 1L O2 at STP

Application based questions on Avogadro's Law: avogadro's law problems with solutions

1. Suppose we have 12.2 L sample containing 0.5 moles oxygen gas at a pressure of 1 atm and temperature of 25 ? C. If all this oxygen were converted into ozone, at the same temperature and pressure, what would be the volume of ozone?

Solution:
The equation for this reaction can be given as follows-

3O2 ? 2 O3
(Oxygen) (Ozone)

In this balanced equation 3 moles of oxygen produce 2 moles of ozone.
In the question given, 0.5 moles of oxygen are reacting. So the number of moles of ozone that it would result

= (0.5 ? 2) / 3
= 0.33 moles of ozone

So, V1 = 12.2 L n1 = 0.5
V2 =? n2 = 0.33

So from Avogadro's Law equation, V1/n1 = V2 / n2,
V2 = (V1 n2) / n1
V2 = (12.2 L) (0.33 moles) / (0.5 moles)
= 8.133 L

2. 11.2 L sample of gas is determined to contain 0.5 moles of nitrogen. At the same temperature and pressure, how many moles of gas would there be in a 20 L sample?
Solution:

V1 = 11.2 L n1 = 0.5 moles
V2 = 20 L n2 =?

From the Avogadro's law,
n2 = (V2 n1)/ (V1)
n2 = (20 L) (0.5 moles) / (11.2 L)
= 0.89 moles

3. Consider the following chemical equation:

2NO2 (g) ? N2O4 (g)

If 25 mL of NO2 gas is completely converted to N2O4 gas, under the same conditions, what volume will the N2O4 occupy?

Solution:
Here, from the equation given, 2 moles of NO2 (g) forms 1 mole of N2O4 (g).

So, V1 = 25 mL n1 = 2 mole
V2 =? n2 = 1mole

V2 = (V1 n2) / n1

V2 = (25 mL) (1 mole) / (2 moles)
= 12.5 mL

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Comprehending Specialized Learning Needs and Various Alternatives (Eblcoaching)

Although nearly all the children are born with normal ability to learn and understand things, yet some of the kids due to neurological problems may face a hard time in learning and carrying out activities that kids of their age can easily perform.

For such children not only learning becomes difficult but they may also face problems while facing a large group of people which can significantly affect their social life as well. However learning can be made easier and effective employing various techniques and the disability does not need to affect an individual's social and personal life.

Learning Disabilities in Children
Kids who suffer from learning disabilities find it hard to cope up with the routine studies at the regular schools. To encourage learning, the parents need to take out extra time for their kids to help them out with school as they can also be successful similar to that of other kids of their standard. To ensure this, it is important to take into consideration the learning difficulty while choosing the classes they already have in school.

How to Improve the Conditions
If you observe the child is struggling at a certain point or perhaps a class, it is essential to talk about the same with the school authorities, find out answers and alternatives as well. One of the best resolutions can be a tutor who can help the kid in his studies before and after the school. Or the parents can also place their kids in special education class for the particular subject.

For instance there is an after school class called Bridges and is designed and intended to aid the kids who find it difficult to read or carry out mathematical operations. Since the class has a limited number of students, the teachers can put more attention on the individual kid pertaining to whatever problem they may have. This sort of learning will help the kid to improve on their weakness in the most desirable manner.

Special education schools are also an option if nothing seems to work out. These schools are ideal when it comes to teaching the children with special needs. They specialize in a number of methods and follow certain techniques to improve learning among the students. Individual Education Program (IEP) is what these approaches are called and adheres to the research based learning techniques.

Specialized Approaches
One such technique is Orton-Gillingham methodology that refers to a systematic and multi-sensory approach that make the kids learn and even the adults suffering from dyslexia or similar kind of disorder. The approach combines plenty of neurological processes at the time of writing or reading by facilitating auditory, visual and kinesthetic learning tasks.The learning programs in Orton Gillingham Tutoring in Bergen County adhere to this approach and are indeed a revolution for the future of instructional theory.

There has been developed a number of research based methodologies to improve learning in the kids suffering from neurological disorders. To learn more about Orton Gillingham Tutoring in Bergen County and other specialized approaches, you may visit www.eblcoaching.com.

Hydrogen Peroxide (h2o2) (Math Help)

Introduction

A pale blue liquid with slightly more viscous than water, and appears colorless in dilute solution. Strong oxidizing properties are exhibited by it, a powerful bleaching agent. It is used as a disinfectant, antiseptic, oxidizer, as a propellant in rocketry. It is considered as a highly reactive oxygen species due to strong oxidizing capacity.

It is produced naturally as by product of oxidative metabolism in organisms. Enzymes known as peroxides, which decompose low concentrations of hydrogen peroxide to water and oxygen without any harm, these are present in almost every living organism.

Uses for Hydrogen Peroxide

IN 1994 about 50% of the hydrogen peroxide manufactured was used for pulp and paper bleaching. As hydrogen peroxide is alternative to chlorine-based bleaches which are environmentally being, other applications for bleaching are becoming more important.

The manufacturing of sodium per carbonate and sodium perforate, used as mild bleaches in laundry detergents hydrogen peroxide is being used. Production of dibenzoyl peroxide organic peroxide used other chemical processes including polymerization.

Epoxides such as propylene oxide production utilize hydrogen peroxide. On reacting with carboxylic acids corresponding per oxy acid are produced.

Hydrogen peroxide mixed with sulfuric acid (in PCB manufacturing process) for copper surface roughening preparation, as a micromesh chemical.

Hydrogen peroxide used in nuclear pressurized water reactors (PWRs) during the plant shutdown in order to force oxidation and dissolution of activated corrosion products which are deposited on the fuel. With the cleanup systems corrosion products are removed before the reactor is disassembled.

Oil and gas exploration industry use hydrogen peroxide in order to oxidize rock matrix while preparing for analysis of micro-fossil.

Biological Function for Hydrogen Peroxide

In bombardier beetle defense system hydrogen peroxide is one of the two chief chemicals, reacting with hydroquinone to discourage predators. In immune system hydrogen peroxide plays an important role. In zebra fish it was found by the scientists that after tissue damage hydrogen peroxide is released, accordingly it is thought that it act as a signal to white blood cells to converge on the site in order to initiate the healing process.

White blood cells did not accumulate at the site of damage when genes required for hydrogen peroxide are disabled. The experiment was firstly conducted on fishes as they are genetically similar to human. There is a higher level of hydrogen peroxide in their lungs of asthma sufferers as compared to lungs of healthy people this is due to inappropriate level of white blood cells in asthma sufferers.

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Magnet Uses (Nandan Nayak)

Introduction to magnet uses:

Magnet is an object that produces a magnetic field. The so called magnetic field is invisible to human eye, but it solely responsible for creating the typical characteristic and property of a magnet, i.e. the invisible force that attracts other various ferromagnetic materials and objects like iron, and attracts and repels other magnets as well. There are permanent magnets that are naturally magnetized and create a consistent magnetic field around them. There are also materials that can be magnetized artificially and hence they get attracted to magnets. These are known as ferromagnetic materials and objects. Another aspect is the electro magnet. An electro magnet is made up of a coil which acts as a magnet when certain electric current passes through it. The magnetic moment determined the overall strength of a magnet while the magnetization determines the local strength of magnetism in a material.

Electro Magnets in details

In simple words, an electro magnet is made up by coiling an electric wire into number of lops called the solenoid. It is when electric current is passed through the wire; it creates a strong magnetic field around it, hence providing it the basic magnetic property of attracting ferromagnetic objects. There are a number of uses of an electro magnet. Electro magnets are used for manufacture of junkyard cranes, particle accelerators, magnetic resonance machines for detecting health problems, for manufacture of electric bells, for manufacture of magnetic locks, for magnetic separation of particles, for manufacture of MRI machines and mass spectrometers and other electro mechanical devices.

Common Uses of a Magnet

There are numerous uses of a magnet. Magnet is used in daily life and also for industrial purposes. It is dynamic and extremely resourceful. Following are some very vital uses of a magnet -

1) Credit Cards and Debit Cards: A wide use of magnets is in the manufacture of credit cards, debit cards and ATM cards. Behind each of these is a magnetic strip. The information is encoded in the magnetic strip and helps to contact the individual's financial institution and connect with their accounts.

2) For manufacture of electric motors and generators: There is a combination of an electro magnet and a permanent magnet found in motors that help to convert electric energy into mechanical energy. The reverse concept is used in generators which coverts mechanical energy into electric energy.

3) Medication: Now days the use of magnets by hospitals has increased substantially. Use of magnets has brought a revolution in the field of surgery and medication. The modern day doctors use the process of Magnetic Resonance Imaging. Through this concept, all the major problems of the patients are diagnosed by the doctors without performing any kind of invasive surgery.

4) For magnetic recording media: Video tapes, Computer Floppies, Hard Disks and etc. use the concept of magnetic reel which helps to encode the information on the magnetic coating which ultimately is transferred in the form of audio and video. This was arguably the revolution as far as the extensive use of magnets is concerned.

5) Miscellaneous: Other very vital uses of magnets are for manufacturing of toys, manufacturing of speakers and micro phones, industrial uses such as lifting heavy iron objects, manufacturing of transformers, for the process of manufacturing of jewellery, for manufacture of chucks that help in the field of metal working etc.

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Convert fraction to percentage (dave hook)

A part of a whole are called fraction. In mathematics, simple fractions can be consisting of minimum two numbers. The numerator specified as top number. The denominator specified as bottom number. Show the fraction form given as below,

Numerator / Denominator

A mathematical expression relating numbers or two quantities, one divided by the other called as fraction. Solve a simple fraction is nothing but it is simplify the fraction using arithmetic operation like addition, subtraction, multiplying, and dividing. Here we are going to see about how to solve a simple fraction

In this page we are going to discuss about Convert fraction to percentage concept.Before that see the introduction to Convert fraction to percentage.

Percent: percent is defined as one of the part of hundred.

Marry scored 88 % of marks in annual exam.

Fraction: A part of a whole thing is called as fraction. It is like, if a cake divided into four parts then those parts are called fraction in math ( [1/4] ).

Changing of fraction to percentage is done by dividing the given number and a decimal value is obtained as a result. Then multiply the result with 100 then the solution is changed from fraction to percentage.

How to convert fractions to percentages

Below are the steps for converting fractions to percentages:

We have to convert the denominator part of the fraction to 100.
We multiply by 100 both the numerator and denominator and simplify.

Example : How to Convert the fraction 12 to percentage

Solution: We simply multiply both the numerator and denominator by 100 and do the cacellations.

12?100100=1?1002?100=50100=50 %The denominator is 2 . 100 divided by 2 is 50.

Solved Examples

Let us solve some example problem to learn how to convert fractions to percentage:

Ex 1: How to Convert fraction 18 to percentage.

Sol : We multiply 100 with both the numerator and denominator. 100 divided by 8 is 12.5

18=18?100100=1008?1100=12.5100=12.5%

Ex 2: How to Convert the fraction '1/25' to percentage.

Sol: We multiply both numerator and denominator by 100. 100 divided by 25 is 4.

'1/25 = 1/25 xx 100/100 = 100/(25xx100) = 4/00 =4%'

Ex 3:How to Convert 33 ? to percentage.

Sol : First we convert the mixed fractions to improper fractions and then to percentage

'33 (1/4) = ( (33 xx 4 ) +1)/4' '=( 132+1)/4 = 133/4'

Now we convert 133/4 to percentage

'133/4 xx 100/100 = 133 xx 100/4 xx 1/100 = 133 xx 25 %' = 3325%

Ex : 4 A class has 40 students .Out of that 25 are boys and remaining are girls. Find what fraction of the class is boys.Also give the answer in percentage of boys and girls in the class.

Sol : Total number of students in the class is 40

Number of boys is 25

Fraction of boys is '25/40 = 5/8'

Fraction of girls is '15/40 = 3/8'

Percentage of boys is '5/8 xx 100/100 = 5 xx 12.5 %' =62.5%

Percentage of girls is '3/8 xx 100/100 = 3 xx 100/8 xx 1/100 = 3xx12.5%' =37.5%

Ex 5: A basket has fruits . one third is apples , two thirds is oranges.Find the percentage of each fruit.

Sol : Apples is one third = '1/3'

Oranges is two third = '2/3'

Percentage of apples = '1/3 xx 100/100 = 100/3 xx 1/100 = 33.33%'

Percentage of oranges = '2/3 xx 100/100 = 2 xx 100/3 xx 1/100 = 2 xx33.33%' =66.66 %

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Chemicals in Food (p Nitin)

The food contamination by hazardous chemical is a universal health concern and is a most important cause of every problem globally. The occurrence of contamination is through several environmental pollution or through the intended use of different chemicals, such as pesticides, animal drugs and other agrochemicals.

While in 1976, the WHO implement the Global Environment Monitoring System - Food Contamination Monitoring and Assessment Programme (GEMS/Food), which has educated governments, the Codex Alimentarius Commission and other related institutions, as well as the public, on levels and trend of contaminants in food, their part to total individual exposure, and implication with regard to public health and trade.

Food additives and contaminants resultant from food mechanized and dispensation can also harmfully affect health.

Chemicals in food

A wide range of activities have been developed to estimate the security of food components. The International Programme on Chemical Safety (IPCS) has developed this type of safety measures.

These actions provide the secretariats and technical advice to the Joint authority on Food Additives (JECFA) and the Joint Meeting on Pesticide Residues (JMPR) and carried out worldwide risk assessment of chemical anxiety such as acryl amide, formed as a derivative of food processing and cooking.

For the estimation of chemicals in food, as with other chemicals evaluation work, the development, organization and use of globally established, systematically sound and translucent principles and method is essentially important.

List of Chemicals in foods

Food Chemicals: Acetic acid, citric acid, tartaric acid, meleic acid, gems powder, sorbitol, propyl glycol, calcium propionate, bakery chemicals, flavoring chemicals, potassium meta bisulphate, menthol, peppermint, thymol ammonium bicarbonate, ammonium carbonate, pectin, sodium benzoate, butyrate, hydroxyl, anisole, etc.

General Chemicals in foods: Caustic soda flakes, caustic potash, sodium nitrate, sodium nitrite, sodium sulphate, sodium bicarbonate, soda ash, calcium carbonate, calcium sulphate, zinc sulphate, zinc oxide, hydrochloric acid and hydrofluoric acid

Industrial Chemicals: Caustic soda flakes, potash flakes, nitrate, sodium nitrite, sodium sulphate, sodium bicarbonate, soda ash, calcium carbonate, calcium sulphate, zinc sulphate, zinc oxide, hydrochloric acid, hydrofluoric acid, toluene, phenol, benzene, cyclohexane, carbon tetra chloride, methyl dichloride.

Chemicals used in Paints and Inks: Rosin, turpentine, pine oil, mineral turpentine oil, ethyl silicate, phenol, butyl acetate, ethyl acetate, methanol, propyl glycol and titanium oxide

Chemicals used in Pigment Color: Red, green, beta blue, yellow and pink

Chemicals used as Disinfectant: Instrument cleaner, chlorohexadine, chloramines, benzalkonium chloride, Lysol, sodium benzoate, potassium permanganate, alum, hydrogen peroxide, mouth cleaning chemicals, ethanol and ISO propyl alcohol

Solvent chemicals: Toluene, benzene, phenol, hexane, heptanes, industrial solvent base oil, rubber process oil, M.E.K., M.I.B.K.

Dental Chemicals: The dental chemicals as follows compound of Fluorine, mercury, meleic acid, benzalkonium chloride tartaric acid and calcium sulphate

Leather Chemicals: The leather chemicals as follows sodium nitrate, softener, resorcinol, sodium benzoate and basic color

Water Treatment Chemicals: Alum, poly aluminum chloride, polyelectrolite, sodium hexameta phosphate, disodium phosphate, potassium permanganate, lime powder, sodium hypochlorite, bleaching.

Understand more on about the Definition Nomenclature, and its Illustrations. Between, if you have issue on these Expanded Octet Rule keep verifying my content i will try to help you. Please discuss your feedback.

Electrical Wire Terminal (Math Help)

Terminal Supply's updated and enhanced website. You may have noticed some remodeling has taken place on this site and we would like to better acquaint you with some of the new features. Our new navigation bar at the top of every page allows you to browse the contents of this site quickly and easily through streamlined drop down menus. The Product Catalog page has been updated to include a greater number of categories and sub categories so you can find exactly what you need in a matter of moments. Our goal is to improve your virtual experience with Terminal Supply Co. and we will be continually updating and refining the look and function of our site to guarantee a satisfying online encounter.

For over 40 years we have become a trusted supplier to the heavy-duty and industrial markets because of the quality manufacturers that we stock. Our electrical line includes Molex heat shrink terminals and Bussmann fuses and circuit breakers. We carry a wide inventory of Cole Hersee switches and solenoids . 3M electrical tape and Hellerman Tyton cable ties also complement our electrical product line. Our selection of heat shrinkable tubing is selected from the top producers in the country.

If you are searching for LED truck lights, you have come to the right place. We are adding new products to our website from top companies including Truck-lite, Vehicle Safety, Grote, Optronics and Maxxima. Our inventory depth of Ecco back-up alarms , strobes, and LED warning lights are sure to get your vehicles noticed. Whether you are shopping for a Target Tech light bar or a Star Warning Systems strobe light, chances are that it's on the shelf. One of our latest product lines we have added recently is Eaton Weatherhead brass , hose and hydraulic fittings. As always, feel free to call us anytime to check our stock as we add our inventory to our website.

Our extensive inventory of solderless wire terminals here at Nelco Products, including non-insulated, vinyl insulated and nylon insulated wire terminals, as well as heat shrink insulated and high temperature terminals, offers a wide assortment of reliable solderless wire terminal solutions to effectively meet the needs of a broad range of electrical wiring applications.

From solderless ring terminals, electrical terminals, spade terminals and flanged block spades to male and female quick disconnects, male and female couplers, wire crimpers, plus a host of other top quality wiring accessories, here at Nelco Products we've got all of your electrical wiring project needs covered right here in one convenient online location!

Maney Wire & Cable stocks a full line of electrical wire terminals including butt splice connectors, bullet connectors, ring terminals (eyelets), spade terminals (forks) in block spade, flanged spade, and snap spade styles. Our electrical terminals come in a variety of insulation styles such as non insulated, vinyl insulated, nylon insulated with extra crimp sleeve and heat shrink insulated. We also carry related tools such as crimp tools, cutting tools, and heat guns. Most of the products we offer are made in the USA. Whether you need 100 terminals or 100,000, you will find we have a nice supply and great wholesale pricing at all quantity levels. Click on the type you are looking for to get more information or call us today at 877-4MY-WIRE. You can also send us an email. We will be glad to help.

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Human Evolution Natural Selection (Omkar Nayak)

Introduction to human evolution natural selection:

Human evolution is scientifically known as anthropogenesis. The scientific name of Human is Homo sapiens. The study of human evolution involves many scientific disciplines such as physical anthropology, archaeology, linguistics and genetics. Human evolution is scientifically known as anthropogenesis. The scientific name of Human is Homo sapiens. The study of human evolution involves many scientific disciplines such as physical anthropology, archaeology, linguistics and genetics. Humans evolved from other hominids, great apes and placental mammals in million of years

Scientists have estimated that humans evolved from their common ancestor with chimpanzees about 5-7 million years ago though the direct lineage from the ancestor of both man and the modern apes to modern man is not known.

Apart from modern apes human shared a common ancestor with whales, chimpanzees and with kangaroos. Studies show that human and chimpanzees shared a common ancestor about 8 million years ago. With whales, common ancestry is tracked about 60 million years ago. Kangaroos and Human shared ancestry about 100 million years ago.

About natural selection:

Natural selection is predictable and efficient mechanism of evolution. Due to evolution species adapt to their environment. It shows the reproductive success of a species, their design in nature and evidence of evolution in action. Due to several environmental and climatic changes individuals needs certain characteristics to have a greater survival or reproductive rate than other individuals in a population. Natural selection leads to evolutionary changes in individuals and pass on these inheritable genetic characteristics to their offspring.

Natural selection as an agent of evolution:

Species come to possess genetic adaptations to the environment due to process of evolution and its working mechanism is natural selection. The process of natural selection acts through individuals and it determines which individuals have the best adaptations for reproductive success.

Natural selection is the central idea of Charles Darwin and Alfred Russel Wallace. The term was introduced by Charles Darwin in one of his books. The struggle for resources or struggle for existence will favor individuals with some variations over others and thereby change the frequency of traits within the population. This process is natural selection and the traits that have an advantage to those individuals who leave more offspring are called adaptations.

Although It is not the only mechanism of evolution but one of the most responsible process for the evolution. There are many difference of opinions among scientist regarding Theory of Evolution and natural selection but over time enough evidence accumulated to support evolution and natural selection.Now when Evolution is a fact, Natural selection is the best process which explains it.Evidence of natural selection are well-documented by observation and through the fossil record.

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Free Online Course Materials (Math Help)

Introduction to Free Online Course Materials

Free online course materials for mathematics makes the student to download mathematics content from online and also to interact with the online tutors and let them to clear their doubts in mathematics course materials. Free online course materials are one of the instant types of learning where student can solve the problem easily with the guidance of online educators. Free online course materials are accessed easily from the internet at free of cost.

Free Online Course Materials

Free online course materials for mathematics consist of many topics. It is mainly used for those who are searching for mathematics contents and also to get prepared with the mathematics for the students of kindergarten to college grade.

The major topics in the free online course materials for mathematics are Algebra, Calculus and analysis, Trigonometry, Geometry and topology, Combinatory, Logics, Number Theory, Differentiation, Integration, etc. Some of the major topics are explained below.

Trigonometry Functions:

* Solving trigonometric functions take main part in trigonometry. Solving trigonometric functions involves with the properties of right triangle.

* First we have to study about the trigonometric functions which are sine, cosine, tangent and their reciprocals are cosecant, secant, and cotangent. Also these are called identities which are used to learn and solve trigonometric functions.

* Also Pythagoras Theorem of a2 + b2 = c2 is used to solve the right angled triangle.

The trigonometric functions have the following properties.

Sine = '(opposite)/(hypotenuse)'

Cosine = '(adjacent) / (hypotenuse)'

Tangent = '(opposite) / (adjacent)'

Cotangent = '(adjacent) / (opposite)'

Secant = '(hypotenuse) / (adjacent)'

Cosecant = '(hypotenuse) / (opposite)'

Algebra:

By using Algebra, the unknown values are solved with the help of known value. Also factoring of the equation is used to find the value of the variable. Algebra course materials involves in the areas of mathematics and science. Algebra online course materials help in solving wide range of problems from mathematical word problem to complicated problems in science.

Problems for Free Online Course Materials

Problem 1: Solve the equation, -5x + 20 = 25

Solution:

-5x + 20 = 25
-5x + 20 - 20 = 25 - 20 Subtract 20 on both sides.
-5x = 5 Divide negative five on both sides
-5x / -5 = 5/-5
x = -1

Problem 2: Solve the equation, -0.30x + 2.3 = -0.5x - 0.2

Solution:

-0.30x + 2.3 = -0.5x - 0.2
-0.30x + 2.3 - 2.3 = -0.5x - 0.2 - 2.3 Subtract 2.3 on both sides
-0.30x + 0.5x = -0.5x - 2.5 + 0.5x Add 0.5x on both sides
0.2x = - 2.5 Divide 0.2 on both sides
x = -1.25

Problem 3: The sides of right-angled triangle are 20cm and 30 cm. Find the another side.

Solution:

By Pythagorean Theorem,

C^2 = a^2 + b^2

C^2 = 20^2 + 30^2

c^2 = 400 + 900

c^2 = 1300

c = 36.05 cm

Therefore the hypotenuse is 36.05 cm.

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Preschools in Pune - Develops and Enhances Your Child Growth (Little Millennium)

Folks dependably attempt to accommodate the best for their kids. Numerous folks are of the perspective that right from their kid, should deserve the best. In the prior days, the small youngsters would formally begin set to class at the age of four or five. Be that as it may, the present era children are currently being presented to early childhood education all over the world.

Instead of accepted family standards, a hefty portion of today's children seem to be raised in a nuclear family. Their right to gain entrance to their larger family is just restricted. Moreover, today's economy has compelled both folks to enter the workforce to give a not too bad expectation for everyday comforts for their kids. This leaves the kid in a powerless position as the kid dependably needs nurture, mind, and love.

Because of the forces of up to date living, the more youthful kids are left without forethought much of the time. For numerous folks, the appearance of Preschools and Nursery school in Pune is acknowledged as a welcome step. In this manner, kids can get the chance of staying with other youngsters of their age this school and use a couple of hours amidst prepared educators and other staff. Hence, they can have fun in playing and study in the meantime. This is precisely the thought of this sort of school.

Pune city in Maharashtra state of India has adequate scope for business and is an essential business focus. This town has the best chances regarding such schools as by and large. In this manner, These Nursery Schools in Pune are the best alternative with regards to furnishing adolescent youngsters and minor tots with the best in education. Huge numbers of these schools use reasonable techniques for educating while the kids play.

This is supportive as kids have the capacity to utilize their sensitivity while they play. In this manner, more youthful youngsters get a great opportunity to advance their emotional disposition and enhance their conveyance abilities while they are still junior. Numerous playschools likewise instruct great and nurturing tendencies while they prepare them too to take part in numerous fascinating exercises. This keeps the kid intensively involved and preoccupied in amusements as they study.

Preschools teachers are uniquely prepared to make the toddlers feel at home while they are studying and playing at school. Various essentially situated diversions cause the kids to enhance their abilities and furnish them with the wellspring of quality and strengthen it. At Preschool In Pune is hence the right nurturing place for the cultivating and improvement of old youngsters. Folks in this manner need not waver to concede their kids to any nursery school as these are there for their generally speaking profit.

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Helping Primary Pupils Who Have Limited English (Hannah McCarthy)

The number of children entering UK schools who have limited English or who can't speak it at all is increasing. This means that language barriers in classrooms are becoming an ever more common problem, one which head teachers and staff will have to work hard to address to keep their school's standards high and avoid criticism from Ofsted.

The growing number of pupils whose first language is not English has seen some schools in certain regions come to comprise of more non-native English speakers than English-speaking children. In schools where there are such statistics teachers are likely to find it a struggle to get their pupils to the required standards especially as sometimes children who can't speak English may have limited opportunities to speak with fluent peers.

In February, the papers were all talking about the first discovered primary school to have an entire student base made up of pupils learning English as an additional language (EAL), which, despite the hurdles and challenges it faced, managed to achieve a 'good' rating from Ofsted. If Gladstone Primary, with 450 pupils speaking 20 different languages managed to overcome its previous 'inadequate' Ofsted rating after just over a year, then surely there are some practices schools can employ to make sure all their pupils, whatever their mother tongue, can do their best?

Methods for helping EAL pupils
Some practices which Gladstone Primary and other primary schools with a diverse student body have used to good effect include buddy systems and mentoring. Gladstone's buddy system partners pupils with English speaking pupils from other schools so that they can play and learn together in each other's schools once a fortnight. For the English speaker, this helps them to learn about other cultures while the non-English speaker benefits from learning English from a peer in a casual and fun environment where they are less shy. Schools which have a mixture of English speakers and non-English speakers can do this within their own school to encourage integration. In Cambridge, the Bell Foundation has launched an initiative to have sixth formers from local private secondary schools trained to act as special mentors.

Other outside help some schools use are teaching assistants. Some primary schools have employed people from the community who speak one or more foreign languages to assist in classes and help children having any difficulty with the English so that they can follow and keep up with the lesson.

Teachers themselves can also do a lot to help their students with limited English. Aside from being encouraging and approachable, there are various techniques teachers can use to lighten the environment so that children aren't afraid to ask questions. Running through the English vocabulary for a new topic at the start of the lesson suggests to children that they are not expected to know every word so they don't have to worry if they stumble across something new. Equally, providing a running commentary through lessons ensures that teachers help students to match objects to words.

Lastly, the schools which are really successful when it comes to integrating their EAL pupils and helping them with their English are those which reach out to the parents. Having a good website, language help for parent's evenings and parent workshops encourages foreign parents to take an interest in their child's learning without feeling intimidated.

Hannah McCarthy works for Education City, which provides eLearning teaching resources, for maths, English, science and foreign languages. Education City's website also provides resources for learning English as an additional language.

Statistics Median Online Tutor (p Nitin)

The median of a finite list of s can be found by arranging all the observations from lowest value to highest value and picking the middle one. If there is an even of observations, then there is no single middle value; the median is then defined to be the mean of the two middle values.

-Source Wikipedia.

Statistics is the proper science of creating well-organized use of numerical data between the sets of individuals. We can study the statistics in web sites. The web sites are providing the lot of definitions and example problems.

The online tutoring for the median is much helpful to the students to learn. By the online tutoring, students will get the help very interactively and also students can learn from their place.

Example to statistics median online tutor:

Example 1 by statistics online tutor:

Calculate the median for the given set of values. 23, 22, 86, 38, 30, 92, 26.

Solution:

First we have to arrange the given set of values in ascending order.

The ordered list of given set of values is 22,23,26,30,38,86,92.

Here, the given set is odd. So we have to pick out the middle.

Therefore, the median of the set of values is 30.

Example 2 by statistics online tutor:

Calculate the median for the given set of values. 48, 97, 55, 82, 27, 13, 14.

Solution:

First we have to arrange the given set in ascending order.

The ordered list of given set of values is 13,14,27,48,55,82,97

Here, the given set is odd. So we have to pick out the middle.

Therefore, the median of the given set of values is 48.

Example 3 by statistics online tutor:

How to find the median for the given set of values. 13, 78, 44, 61, 60, 77, 58, 20

Solution:

First we have to arrange the given set of values in ascending order.

The ordered list of given set of values is 13,20,44,58,60,61,77,78.

Here, the given set of values is even.

So we have to pick out the middle of two s and we have to solve average or mean of those values.

Therefore, the median of the set of values is '(58+60)/2' = 59.

Example 4 by statistics online tutor:

Calculate the median for the given set of values. 100, 26, 3, 80, 3, 48, 36, 11.

Solution:

First we have to arrange the given set of values in ascending order.

The ordered list of given set of values is 3, 3, 11, 26, 36 ,48, 80, 100.

Here, the given set is even.

So we have to pick out the middle of two s and we have to Solve average or mean of those values.

Therefore, the median of the set of values is '(26+36)/2' = 31.

Practice problems to statistics median online tutoring:

Problem 1 by statistics online tutor:

Calculate median for the given set of values. 95, 95, 4, 18, 79, 66, 97.

Solution: The median of the set of values is 79.

Problem 2 in online tutoring:

Calculate the median for the given set of values. 1, 71, 21, 67, 95, 3, 97, 6

Solution: The median of the given set of values is 44.

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Wind Electric Power (Omkar Nayak)

Introduction to wind electric power:

Wind electric power is generated by harnessing the wind energy to generate the power It is the world's fastest growing energy source. Wind electric power is becoming an important resource to meet the increasing power demand as wind energy is a renewable and free resource.

Generation of wind:

Wind is a form of solar energy. Winds caused by the uneven heating of the earth's surface by the sun due to irregularities of the earth's surface and by the rotation of the earth. Wind flow are change by the earth's geographical conditions. This wind energy can be "harvested" by modern wind mills which converts the kinetic energy of wind to generate electricity.

Wind turbines or wind electric generators convert the kinetic energy of the wind into mechanical power.This mechanical power rotates the turbine blades which rotate rotor of the generator that convert mechanical power into electrical power.

Generation of wind electric power

The energy of the wind will be harnessed with wind electric generators or turbines. When the wind flows that passes the turbine's rotor blades, the blades rotate and convert the wind energy into kinetic energy. This Kinetic energy of blades makes the rotor to spin inside a generator according to Faraday's law of electromagnetic induction the kinetic energy is converted into electrical energy. Once the wind energy is converted into electrical energy, the electrical energy flows through power cables in the turbine down's to the turbine tower to connect with the output of the other wind turbines in the wind farm before entering into power transmission. The wind generated power is directly proportional to the wind speed. The greater is the wind speed, the more electrical energy it will be generated. In Wind farms we will see more than one wind turbine working to generate electricity - this is called a wind farm. All the wind turbines will work independently and generate individual power that will be collected from all the wind turbines before feeding for transmission networks.

Construction of wind electric generator to generate wind electric power

Each wind turbine or electric generator has four key parts:

Foundation: Wind turbine is a massive structure that must have a strong foundation to withstand the force from strong winds and it has to support the overall height and the length of the rotor blades.

Tower: Power generation equipments is kept in the tower. The tower consists of the blades and power generation equipments high above the ground level into the smoother where stronger wind currents are blowing. Access to the nacelle and rotor can be done through the tower.

Nacelle: The nacelle can be simply said as heart of the turbine, where the generator, gearbox and turbine drive train parts are held. The generator set inside the nacelle is used to convert the wind energy into kinetic energy and then it will transform into electrical energy.

Rotor: Almost wind turbines have three blades that are attached to the rotor. Blades in wind turbines tested thoroughly to ensure that they can withstand most severe weather conditions.

Generator: When the rotor rotates inside the magnetic poles or stator of the generator according to Faradays law of electromagnetic induction that is "the EMF induced in a coil is directly proportional to the rate of change of flux linkage.This generated power is step up with a transformer and feed to transmission networks.

Pros and Cons of wind electric power

Pros of wind electric power:

Wind energy is a Renewable source and Non-Polluting Resource.

Wind energy is a source of clean, non-polluting form of generation of electricity.

Unlike conventional power generation plants the wind plants does not cause air pollution or emitting of greenhouse gases.

Cons of wind electric power:

The initial installation cost of the wind generator is very high due to utilizing of sophisticated equipments.

Rotor rotation produces much noise resulting in noise pollution.

Power generation is directly depends upon the availability of wind energy which is unpredictable.

Wind mills need to be generated in remote areas where the wind resource is abundant so power transmission and installation cost is high.

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Solve Learning Statistics (p Nitin)

In math, Statistics is the formal science of making effective use of numerical data connecting to groups of individuals or experiments. It contracts with all features of this, including not only the group, analysis and interpretation of such data, but also the planning of the group of data. Now we will discuss about how to solve and learning the statistics with some of the statistics example problems. (Source: Wikipedia).

Learning statistics:

In math, the statistics is very useful and important factor.
In statistics, the mean, median, range, and mode these are mostly used to learning the statistics.
Now we will learn the statistics with some of the examples.
Mean:

In solve learning statistics; the mean is detail about the middling of the given numbers.
So now we will find out the adding of the given numbers and divided by the total numbers of the given numbers.
Additions of the given numbers are 11, 25, 87.
= 11+25+87=123.

At this second divided by 3, because (Notes: 3 is the total given numbers whole)
= 123 / 3= 41.

Median:

In solve learning statistics; the median is described about the midpoint value of the given series.
The number series are 11, 25, 87.
The numbers in the middle of point of the above series are 25.
Therefore 25 is the median of the given series.

Mode and range in solve learning statistics:

Example of solve learning statistics:

Mode:

In solve learning statistics, the mode is prove again value of the specified number series; the particular value is shows again continually.
This is known as mode in solving statistics.
Example of mode: 11, 25, 87.
In this series are the no values are shows repeated.
So in this series the mode is blank.
Range:

The differentiation between greatest value and the lowest value is well-known as the range of the series.
87-11=76.
Therefore 76 is the range of the series in this series.

This is known as solve learning statistics.

Problem 1

Solve the mean, median and range of the following numbers in statistics?

16,18,21,26,28,31,35.

Solution

The given numbers are 16,18,21,26,28,31,35.

Mean

Mean is the average of the given number. Calculate the average with the help of total value of the given sequence.

Sum of the given numbers are = 16+18+21+26+28+31+35.

= 175.

Total values are divided by 7 (7 is the total numbers) = '(175)/(7)'

= 25.

Median

Center element of the given series is a median.

The number series is 16,18,21,26,28,31,35.

The middle element of the above sequence is 26.

So median=26.

Range

Less the low value from the high value.

Range=35-16

=19.

Example 2

Find out the mean, median, mode and range of the below numbers in statistics?

21,26,28,31,34,37,42.

Solution

The given numbers are 21,26,28,31,34,37,42.

Mean

Mean is the average of the given number. Calculate the average with the help of total value of the given sequence.

Sum of the given numbers are = 21+26+28+31+34+37+42

= 219.

Total values are divided by 7 (7 is the total numbers) = '(219)/(7)'

= 31.2.

Median

Middle element of the given series is a median.

The number series is 21,26,28,31,34,37,42.

The middle element of the above sequence is 31.

So median= 31.

Mode

Mode is the duplication of the series. The given sequence no copy value. Therefore the mode is empty.

Range

Less the low value from the high value of the series.

Range =42-21

=21.

These are the examples are helps to study the statistics in tutoring time.

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Energy Wavelength Relationship (Math Help)

Unit Analysis

Sometimes you want to express a measurement in different units. For example, when talking about how far away something is, sometimes it may be useful to say it is a certain DISTANCE (New York is 300 miles from here), and sometimes it is more useful to use TIME to express how far away it is (New York is a 6 hour drive from here). Of course miles are not equal to hours, so there must be some way to convert from one to the other. In this case, the conversion is speed: if a car drives an average of 50 miles/hour, then it can drive 300 miles in 6 hours. For this constant speed, 300 miles equals 6 hours.

Problem

1. If you walk at a speed of four miles an hour, and your friend lives two miles away, how far away is her house

a. in miles
b. in minutes, if you are walking
c. in minutes, if you are driving at an average speed of 25 miles an hour

In much the same way, different units can be used to characterize light. We can refer to light by its wavelength, its frequency, or its energy. This is similar to talking about distance in units of miles or hours.

I. Wavelength --> Frequency

Light waves travel at a constant speed. Because of this there is a one to one relationship between light's wavelength and its frequency. If waves are short, there must be more of them in a set amount of time to travel the same distance in that time (the same speed).

Problems

2. The speed of light is 186,000 miles per second. What is the frequency of light that has a wavelength of three feet? two inches? 1/1,000,000 inches? one mile?

3. What is the wavelength of the radio waves of your favorite radio station? (HINT: the frequency of radio stations is equal to the station number times 1,000,000 Hz. So WAMU - National Public Radio - at FM 88.5 - is 88,500,000 Hz. Now, use the fact that the wavelength is equal to the speed of light, a constant, divided by frequency.)

In 1900, Planck discovered that there was a direct relationship between a photon's frequency and its energy:

E = h nu

The higher the frequency of light, the higher its energy. We know from the problems above that higher frequencies mean shorter wavelengths. We can also say that E = h c / lambda. High frequency light has short wavelengths and high energy. X-rays or gamma-rays are examples of this. Radio waves are examples of light with a long wavelength, low frequency, and low energy.

In much the same way, the gallons of gas you put in your car and the cost of the gas are proportional: the same value multiplied by a constant (the price of a gallon of gas). If you know the constant (the price per gallon) and you know the number of gallons, you can calculate how much the gas costs. Or, if you know how much the gas cost, you can calculate how much gas was bought.

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Concentration Of Ores (Math Help)

Introduction to concentration of ores:

The process of extraction of metal in the free state from its ore is called Metallurgy.Some common steps involved in the metallurgical operations are:

1. Crushing and grinding of the ore.

2. Concentration or benefication of the ore.

3. Production of metal from the ore.

4. Purification of the crude metal.

Here,we shall be discussing in detail about "concentration of the ore"

Benefication of ore concentration:

The ore obtained from the earth's crust is associated with rocky and silicon impurities.It is essential to get rid of these impurities so that they may not interfere in the process of extraction.The removal of impurities from the pulverised ore is called concentration or benefication of ore.The benefication of the ore is carried out by any of the following methods depending upon the nature of the ore and also the impurities present in the ore.

Process of ore concentration:

(i)Levigation or gravity separation method:This method is usually applicable to oxide ores in which the ore particles are heavier than the impurities.The powdered ore is washed with running stream of water.The lighter impurities are washed away leaving behind the heavier ore particles.

(ii)Froth floatation process:This process is generally used for the concentration of sulphide ores.The finely powdered ore is taken in a mixture of water and pine oil.The oil acts as a frothing agent.The contents are kept agitated by a blast of air.As a result of agitation,the froth is produced.The ore particles are preferentially wet by the oil and are carried to the surface by the foam. The gangue material which is preferentially wet by water sinks to the bottom of the tank.The foam at the surface is transferred to another tank where it is washed with water to recover the ore particles.

(iii) Magnetic separation of impurities:This method is usually employed for the separation of magnetic impurities from non -magnetic ore.For example,tungstates of iron and manganese from tin stone are separated by this method.The powdered ore is dropped over a belt revolving around the rollers,one of which is magnetic.The magnetic rollers attract the magnetic part of the ore and they are collected in a heap in front of it.

(iv) Leaching: It is a chemical method for the concentration of the ore.In this process,the powdered ore is dissolved selectively in certain acids,bases or other suitable reagents.The impurities remain undissolved as sludge.The solution of the ore is filtered and the ore is recovered by precipitation or crystallisation.

Besides these methods,other methods of concentration of ores are also used which are based on specific properties.Some of these are:electrostatic separation,amalgamation,liquation and optical separation etc.

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Substitution Method (Math Help)

The Substitution method is a method for solving equations with more than one variable. This method is very useful in equations with two variables and is commonly used in solving a pair of linear simultaneous equations. The first equation is solved for one variable in terms of the other and this value is substituted in the second equation. This is illustrated below with examples

Introduction for substitution method variables:

* Substitution method is commonly used to solve a pair of linear simultaneous equations. Linear simultaneous equations can be solved by two methods one is elimination method another one is substitution method.

* Given two equations, solve for one variable from one of the equations and then substitute the value of that variable into the other equation

How to solve by substitution method

1) Solve the two equations using substitution method to find the variable x and y.

3x + 4y = -9

y + 8 = 5x

Solution:

Step 1: First choose an equation where the variable is 1.So choose the equation 2.

y = 5x - 8

Step 2: From the previous equation we know that variable y is same as 5x - 8

3x + 4(5x - 8) = -9

3x + 20x - 32 = -9

Step 3: Combine the terms

23x = 23

X = 1

Step 4: substitute the value x in equation 1

3x+4y=-9

3(1) +4y=-9

3+4y= -9

4y=-9-3

y = -3

The solution is, x = 1 and y = -3

2) Solve for Variables x and y, where, 2x + 2y - 6 = 0 and 3x + y + 4 = 0.

Solution: 2x + 2y - 6 = 0 ? (1)

3x + y + 4 = 0 ? (2)

Let us consider the equation (1) => 2x + 2y - 6 = 0

=> 2y = - 2x + 6

=> y = -x + 3 ? (3)

Now, plug equation (3) in equation (2).

(2) => 3x + y + 4 = 0

=> 3x + (-x + 3) + 4 = 0

=> 3x - x + 3 + 6 = 0

=> 2x + 9 = 0

=> 2x = - 18

=> x = - 9

Now, plug x = -9 in Equation (1).

(1) => 2x + 2y - 6 = 0

=> 2(- 9) + 2y - 6 = 0

=> - 18 + 2y - 6 = 0

=> 2y - 22 = 0

=> y = 11.

The solutions are x = - 9 and y = 11.

3) Solve the equations by using the method of substitution and find the variables x and y.

2x - y = -5

3x+8y =-55

Solution:

Step 1: Rearrange the first equation,
2x - y = -5
y = x + 5

Step 2: Substitute 1st equation on equation 2

3x + 8(2x + 5) = -55

Step 3: Expand and simplify the equation:
3x + 16x + 40 = -55
19x = -95
x = -5

Step 4: Substitute x values in 1st equation

2(-5) - y = -5

-10-y=-5

-5=y

Y=-5

Solution: x = -8, y = -5

Steps to solve substitution method:

Step 1: For solving substitution method to write a variable in terms of another variable.

Step 2: Then substitute that equation in second equation to get a single variable equation.

Step 3: In the next step to solve that single variable equation and then to find the value of that variable.

Step 4: Once we get the value of one variable, substitute that value of variable in any of the equation to get the value of the second variable.

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Learning Logarithmic Function Problem (Nandan Nayak)

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Prepare For 7th Grade Math Practice (Nandan Nayak)

Introduction to prepare for 7th grade math practice:

The preparation of 7th grade math practice includes the topics of Number theory, Operations with integers, Decimal numbers, Operations with decimals, Integers, Operations with fractions, Rational numbers, Pythagorean theorem, Exponents and square roots, Fractions and mixed numbers, Ratios and proportions, Number sequences, Measurement, Charts and graphs, Geometry, Statistics, Transformations, Coordinate graphs, Single-variable equations, Probability. Let, see some of the examples to prepare 7th grade math problems.

Prepare for 7th grade math practice:

Prepare math practice 1:

At a family reunion, each of Connor's aunts and uncles is getting photographed once. The aunts are taking pictures in groups of 2 and the uncles are taking pictures in groups of 8. If Connor has the same total number of aunts and uncles, what is the minimum number of aunts that Connor must have?

Solution:

Write the prime factorization for each number; 2 is a prime number.

You do not need to factor 2.

8 = 2 ? 2 ? 2

Repeat each prime factor the greatest number of times it appears in any of the prime factorizations above.

2 ? 2 ? 2 = 8

The least common multiple of 2 and 8 is 8.

That means that the minimum number of aunts Connor could have is 8, because 4 groups of 2 aunts is a total of 8 aunts and 1 group of 8 uncles is a total of 8 uncles.

The smallest number of aunts is 8.

Prepare math practice 2:

Tatiana placed 9 weights on a scale during science class.

If each weight weighed 0.7 grams, what did the scale read?

Solution:

Multiply the weight of each weight by the number of weights and multiply as you would multiply whole numbers.

0.7
9 ?
________
63

Count the number of decimal places in the factors.

There is 1 decimal place in 0.7.

Move the decimal point 1 place to the left in the answer.

63 ? 6.3

The scale read 6.3 grams.

Prepare math practice 3:

Gabriel owns 10 acres of farmland. He grows beets on 1/5 of the land. On how many acres of land does Gabriel grow beets?

Solution:

Gabriel grows beets on '1/5' of 10 acres of land.

Multiply:

'10xx1/5 =?'

Write 10 is a improper fraction.

'10 = 10/1'

Multiply the numerators and multiply the denominators.

'10/1xx 1/5 = (10xx1)/(1xx5)=10/5'

Simplify the product.

'10/5 = 2'

Gabriel grows beets on 2 acres of land.

Prepare more for 7th grade math practice:

Prepare math practice 4:

Ballet dancers are positioned on stage. If Eve is 9 feet straight behind Curtis and 12 feet directly left of Gun-Woo, how far is Curtis from Gun-Woo?

Solution:

Draw a diagram.

Use the Pythagorean theorem, with a = 9 and b = 12.

a2 + b2= c2

92 + 122= c2

81+144 =c2

225=c2

Sqrt 225 = sqrt c2

15 = c

Curtis is 15 feet from Gun-Woo.

Prepare math practice 5:

A football player named Cole played 40 games last year. This year, he played 5% more games. How many football games did Cole play this year?

Solution:

"5% more" means you should add 5% to the original amount:

100% of original amount + 5% of original amount = 105% of original amount

Write and solve an equation:

Final amount = 105% of original amount

= 105% of 40

= 1.05 ? 40

= 42.

Cole played 42 games this year.

Prepare math practice 6:

Alice's class took a field trip to the art museum. It took them 1 hour to drive to the museum. They stayed at the museum for 3 hours and 15 minutes. When the class left the museum, it was 12:30 P.M. What time did Alice's class leave for the field trip?

Solution:

Add the times to find the total elapsed time.

1 h + 3 h 15 min = 4 h 15 min

Now find 4 hours and 15 minutes before 12:30 P.M.

Count back by hours to find 4 hours before 12:30 P.M.

This is 8:30 A.M.

Now subtract 15 minutes from 8:30 A.M.

This is 8:15 A.M.

Alice's class left at 8:15 A.M.

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Practice Dividing Decimals (Omkar Nayak)

Introduction to Practice Dividing Decimals:

The method for dividing the decimals by decimals is same as dividing the whole numbers. The decimal on the top of the division line is said to be numerator and the decimal on the below the division line is said to be denominator. The condition for the decimals in the division method should not be zero. Dividing the decimals is in the form of a ? b = c. The decimals representing "a" is said to be dividend. The decimals representing "b" is said to be divisor. The resultant answer is called quotient. Let us see about practice dividing decimals in this article.

Procedure for Practice Dividing Decimals

Step 1:

The divisor can be making into a whole number by multiplying both the divisor and dividend by the same number such as 10, 100, 1000, 10000, etc.

Or else move the decimal point to the right side of the divisor and the dividend by the same number of places.

Step 2:

Put the divisor on the left side of the division bracket and put the dividend inside the division bracket.

Step 3:

Multiply the decimals with a number 10, 100, 1000 according to the places given in the problem to make it as a whole number.

Or else if the divisor having two digits after the decimal point, then move the decimal point two digits after the given number in both the divisor and the dividend.

Step 4:

Continue with the dividing method as for whole numbers and put the decimal point in the quotient exactly as it is in the dividend.

Example Problems for Practice Dividing Decimals

Example 1:

Practice dividing decimals 0.99 by 0.3

Solution:

Solution:

Let us write the given problem 0.99 as dividend and 0.3 as divisor.

0.3)0.99(

Step 1:

Multiply the dividend 0.99 ? 10 = 9.9 or else move the decimal point after one digit to make it as a whole number.

Multiply the divisor 0.3 ? 10 = 3 or else move the decimal point after one digit to make it as a whole number.

Step 2:

Put the divisor on the left of the division bracket and dividend inside the division bracket.

3)9.9(

Step 3:

Continue dividing the decimal as on whole number dividing.

Check whether 3 go into 9 for how many parts and multiply the terms of 3 with 1, 2, 3, etc. The number 3 can go into 9 for 3 times and the remainder is 0. Subtract the product from the dividend and put down the next digit to divide.

3)9.9(3

9

---------------

09

---------------

Step 4:

Check whether the number 3 can go into 9 for how many parts and multiply the terms of 3 with 1, 2, 3, etc. The number 3 can go into 9 for 3 times. Subtract the product from the dividend above.

3)9.9(3

9

---------------

09

09

---------------

0

---------------

The decimal appoint can be put as same as in the dividend. In dividend it is before one digit likewise put the decimal point in the divisor as 3.3.

The solution for dividing 0.99 by 0.3 is 3.3.

Example 2:

Practice dividing decimals 0.9846 by 0.18

Solution:

Let us write the given problem 0.9846 as dividend and 0.18 as divisor.

0.18)0.9846(

Step 1:

Multiply the dividend 0.9846 ? 100 = 98.46 or else move the decimal point after two digits to make it as a whole number.

Multiply the divisor 0.18 ? 100 = 18 or else move the decimal point after two digits to make it as a whole number.

Step 2:

Put the divisor on the left of the division bracket and dividend inside the division bracket.

18)98.46(

Step 3:

Continue dividing the decimal as on whole number dividing.

Check whether 18 go into 98 for how many parts and multiply the terms of 18 with 1, 2, 3, etc. The number 18 can go into 98 for 5 times and the remainder is 8. Subtract the product from the dividend and put down the next digit to divide.

18)98.46(5

90

---------------

84

----------------

Step 4:

Check whether the number 18 can go into 84 for how many parts and multiply the terms of 18 with 1, 2, 3, etc. The number 18 can go into 84 for 4 times. Subtract the product from the dividend and put down the next digit to divide.

18)98.46(54

90

------------------

84

72

-------------------

126

-------------------

Step 5:

Continue with the division at last we got,

18)98.46(547

90

------------------

84

72

-------------------

126

126

-------------------

0

--------------------

The decimal appoint can be put as same as in the dividend. In dividend it is before two digits likewise put the decimal point in the divisor as 5.47.

The solution for dividing 0.9846 by 0.18 is 5.47.

More Problems to Practice in Home

1. Divide 0.63 by 0.9.

Key: 0.7

2. Divide 0.3990 by 0.14.

Key: 2.85

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Student Teacher Relationships (Omkar Nayak)

Introduction to student teacher relationships:

Man is a social animal and he makes several relationships. However there is one relationship that teaches him the true value of all the other relationships and that relationship is the student- teacher relationship. A teacher makes a student a sophisticated person and also teaches him to be good all throughout his/her life. In this relationship its not only the student who gains enormous knowledge but it is also the teacher who learns many things from the student. A student's success depends entirely on how a teacher takes this relationship. A lot of understanding is needed while dealing with a student and if the teacher is impatient in handling the student this relationship might loose its charm and it will finally break the mutual understanding of both. Moreover it is important for us to know that not only the emotional and social but also the academic success of a student depends on a teacher. Let us further see the unique aspect of this relationship.

Student- teacher relationship's uniqueness:

Student- teacher relationship is unique in its own way. The unique aspect of this relationship is that the teacher is a colleague/ friend and the teacher as well for a student simultaneously. They share knowledge amongst each other without any selfish motive. If a student studies hard and succeeds in a given field it gives a lot of content and happiness to the teacher. This also makes a tough bond between them. If we leave the relationship at the school level, one of the most satisfying relationships can be seen at the college level where teachers grow with their students. A good student-teacher relationship is basically sharing relationship of something unique that no one else has experienced. But to keep freshness and liveliness in this relationship it is important that both of them respect each other and share things with each other.

Student- teacher relationship and the academic success:

As we spoke about in the previous paragraphs that a student's academic success is dependent on this relationship and hence it also calls for a lot of hard work that each one of them puts to acheive a single goal. To enhance this relationship a teacher must approach the student in a positive way so that the student walks on the right path. With the guidance and motivation of a teacher the student develops and grows in every field. This belief of a teacher in a student helps to boost the morale and confidence of a student which helps the student in a long run. Mutual understanding is the basic thing that both have to develop to make this relationship shine like a bright star in the sky.

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Laser Light Technologies (p Nitin)

A laser beam is a narrow beam of electromagnetic radiation which monochromatic, powerful and directional in nature. The laser beams are found within the visible spectrum of light. The atoms are excited by the laser device in the lasing medium. The electrons of these excited atoms jump from lower orbit to a higher orbit, and then release photons,thus creating a laser beam. The the acronym for LASER is the Light Amplification due to Stimulated Emission of Radiation. Laser can be defined as a mechanism for emitting light or visible light by a laser mechanism called process of stimulated emission. This is called as the electromagnetic radiation. The emitted laser light is generally spatially coherent, narrow beam which can be manipulated with the adjustment or modification of position of lenses. In laser technology, a light source is usually denoted as a "coherent light" as it emits light of in-step waves which are identical in frequency, polarization and phase. The laser's coherent light beam differentiates it from the other light sources which emit different incoherent light beams of random phase which vary along with position and time. Generally, Laser light is a electromagnetic spectrum monochromatic light of narrow wavelength. There are certain type of lasers which emit a broad spectrum of light or different wavelengths of light simultaneously.

A laser consists of gain medium inside an optical cavity which is highly reflective. It also contains a means to supply energy to the gain medium. The gain medium is a material that has properties which allow it to amplify the light received by stimulated emission. In a simple form, it can be explained as a cavity consisting of two mirrors arranged in such a way that light is bounced back and forth each time it is passed through the gain medium. Of the two mirrors, one is the output coupler which is a partially transparent mirror emits the output laser beam.A specific wavelength light which passes through the gain medium is undergoes amplification in order to increase the power and then the surrounding mirrors let most of the light to pass through the gain medium. A part of the light which is between the mirrors i.e., within the cavity passes through the partially transparent mirror and escapes as light.

The different types of lasers are liquid, solid and gas. Gas lasers are used to excite the electrons in gases such as carbon dioxide, nitrogen, helium, neon and cadmium. Liquid lasers such as the dye laser, uses organic dye molecules in the liquid form so as to produce a wavelength of radiation which can be tuned. Solid lasers such as the ruby laser uses a precious stone in order to produce a beam of red colored light.

Laser beams are commonly used in CD and DVD devices, optical scanners, computer mouse, laser printers and pointers for projectors. They are also used to produce hologramson several things. Laser beams are widely used in industry for cutting and welding the metal and to do survey of land and to construct buildings. They are used in scientific research for the chemical analysis and laser spectroscopy. For Dental applications including the treatment of cavity, regeneration of the nerve and reshaping tissue of the gum. In medical procedures such as eye surgeries, cancer treatments and heart surgery as well as in cosmetic procedures also laser beams are used.

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